Part IV · Chapter 12

Moving Average (MA) Models

MA models depend on past SHOCKS, not past observations. Memory is finite: an MA(q) shock only lasts q periods.

\( y_t = \varepsilon_t + \theta\, \varepsilon_{t-1} \)

Learning objectives

Distinguish "MA model" from "moving-average smoother".
Trace a shock through an MA(1) process.
Recognize MA(q) by ACF cutoff at lag q.
Understand invertibility: |θ| < 1.

MA Shock Propagation

Live

Invertibility:
ρ(1) of MA(1):

Shock at t* shows up only at t* and t*+1, then DISAPPEARS — finite memory.

📐 MA(1) properties

\[ y_t = \varepsilon_t + \theta\varepsilon_{t-1},\quad \text{Var}(y_t)=(1+\theta^2)\sigma^2 \]
\[ \rho(1)=\frac{\theta}{1+\theta^2},\quad \rho(h)=0 \text{ for } h>1 \]
θ MA coefficient (signs propagate)
Invertibility |θ| < 1
ACF cuts off after lag q
Memory finite = q periods

🔍 What to look for

⚠️ Pro Tip: What to Avoid

Student says

"MA model means I'm modeling a moving-average smoother."

Why this is wrong

The MA in MA(q) refers to past SHOCKS in a stochastic model, not the descriptive smoothing operation from Ch 5. Different concept entirely.

Correct interpretation

MA(q) is a stochastic process: y_t = ε_t + θ_1 ε_{t-1} + … + θ_q ε_{t-q}.

📝 Mini-quiz

📋 Key Takeaways

QuantityMA(1)
Mean0
Variance(1 + θ²)σ²
ρ(1)θ / (1 + θ²)
ρ(h) for h > 10
Invertibility|θ| < 1