Part IV · Chapter 11

Autoregressive (AR) Models

The current value depends on its own past plus a shock. The parameter φ controls how long memory of past values persists.

\( y_t = c + \phi\, y_{t-1} + \varepsilon_t \)

Learning objectives

Simulate an AR(1) and interpret φ.
Compute the half-life of a shock.
Recognize AR(p) by PACF cutoff at lag p.
Forecast: AR(1) decays geometrically toward the mean.

AR(1) Persistence Slider

Seed:

Live interpretation

φ:
Half-life of a shock: periods
Unconditional variance:

📐 AR(1) properties

\[ y_t=c+\phi y_{t-1}+\varepsilon_t,\quad |\phi|<1 \text{ for stationarity} \]
\[ \rho(h)=\phi^h,\quad \text{Var}(y_t)=\frac{\sigma^2}{1-\phi^2},\quad \text{half-life}=\frac{\ln 0.5}{\ln \phi} \]
φ near 0 weak memory
φ near 1 strong persistence — near unit root
φ negative oscillating series
φ = 1 UNIT ROOT — not stationary

🔍 What to look for

⚠️ Pro Tip: What to Avoid

Student says

"φ = 0.99 is stationary, so it behaves like any other AR(1)."

Why this is wrong

Near-unit-root persistence creates very long-lived shocks, near-non-stationary inference, and unreliable standard asymptotic properties.

Correct interpretation

Treat |φ| close to 1 as "near-integrated" — use robust inference, expect long half-lives, and consider unit-root testing.

📝 Mini-quiz

📋 Key Takeaways

QuantityFormula
Meanc / (1 − φ)
Varianceσ² / (1 − φ²)
ACFρ(h) = φ^h
Half-lifeln(0.5) / ln(φ)
PACFcuts off at lag 1